Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Medical
  • One mole of an ideal monoatomic gas undergoes a process described by the equation . The heat capacity (in terms of R) of the ga

One mole of an ideal monoatomic gas undergoes a process described by the equation PV^3=constant. The heat capacity (in terms of R) of the gas during this process is

Option: 1

1.5


Option: 2

2.5


Option: 3

2


Option: 4

1


Answers (1)

best_answer

 PV^3=K...\left ( 1 \right )

\therefore P=\frac{K}{V^3}
dw=pdv\ or\ w=\int pdv

w=\int_{i}^{f}\frac{K}{V^3}dV= K.\left [\frac{V^{-3+1}}{-3+1} \right ]^{f}_{i}

=K.\frac{1}{2}\left ( \frac{1}{V_i^2}-\frac{1}{V_f^2} \right )

=\frac{1}{2}\left [ \frac{-K}{V_f^2}+\frac{K}{V_i^2} \right ]

From eqn(1),

 \frac{K}{V^2}= PV= nRT

\therefore W=\frac{-1}{2}\left ( nRT_f-nRT_i \right )= \frac{-nR}{2}\Delta T

For monoatomic gas,

\Delta U=\frac{3}{2}nR\Delta T= \frac{3nR\Delta T}{2}

\Delta Q=nR\Delta T

\therefore C= \frac{\Delta Q}{n\Delta T}= R

 

Posted by

manish painkra

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

NEET UG 2026 correction facility opens at neet.nta.nic.in; exam on May 3
anam-khan

NEET 2026 LIVE: NTA application correction window closes today; admit card, exam dates, pattern

Latest Question