Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Medical
  • Record the swing period of the simple pendulum in the experiment are    <img alt="2.63\ s,2.56s,2.42s,2.71\ and\ 2.80s" src="ht

Record the swing period of the simple pendulum in the experiment are    2.63\ s,2.56s,2.42s,2.71\ and\ 2.80s . The mean absolute error is:

Option: 1

0.1\ second


Option: 2

0.11\ second


Option: 3

0.01\ second


Option: 4

1.0\ second


Answers (1)

best_answer

Average value = \frac{2.63+2.56+2.42+2.71+2.80}{5}

                          = 2.62\ seconds

Now,

\left | \Delta T_{1} \right |= 2.63 - 2.62 = 0.01

\left | \Delta T_{2} \right |= 0.06

\left | \Delta T_{3} \right |= 0.20

\left | \Delta T_{4} \right |= 0.09

And, \left | \Delta T_{5} \right |= 0.18

Mean absolute Error is =  \frac{0.01+0.06+0.20+0.09+0.18}{5}

Or, Mean Absolute error =  0.108\ =\ 0.11\ seconds

 

 

Posted by

Pankaj Sanodiya

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

UP NEET UG Counselling 2025: BDS fee structure out for non-minority private dental colleges
anam-khan

NEET admissions, exit tests, registration: NCAHP chief on allied and healthcare sciences’ future
anam-khan

KEA extends Karnataka NEET UG 2025 registration deadline to July 17 for MBBS, BDS, AYUSH admissions

Latest Question