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Be (OH) 2 and Al (OH) 3 upon reaction with a base respectively forms:

 

Option: 1

[Be (OH) 42- and [Al (OH) 4]-

 


Option: 2

[Be (OH) 3] - And [Al (OH) 3] 2-

 


Option: 3

Both a and b


Option: 4

Be (OH) 2 and [Al (OH) 4]


Answers (1)

best_answer

As we learn

Reaction of Berylliumhydroxide and aluminium hydroxide with alkali -

Both gives beryllate ions and aluminate ion respectively

- wherein

[Be(OH)_{4}]^{2-}[Al(OH)_{4}]^{-}

 

 Be (OH) 2 and Al (OH) 3 upon reaction with a base forms beryllate and aluminates ions.

 

Posted by

Ritika Harsh

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