Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Medical
  • Ten moles of an ideal gas at constant temperature is compressed from <img alt="100

Ten moles of an ideal gas at constant temperature 600 \mathrm{~K} is compressed from 100 \mathrm{~L} to to 10 \mathrm{~L}. The work done in the process is

Option: 1

4.11 \times 10^{4} \mathrm{~J}


Option: 2

-4.11 \times 10^{4} \mathrm{~J}


Option: 3

11.4 \times 10^{4} \mathrm{~J}


Option: 4

-11.4 \times 10^{4} \mathrm{~J}


Answers (1)

best_answer

Work done in an isothermal process

\mathrm{W =2.3026 n R T \log _{10}\left(\frac{V_{2}}{V_{1}}\right)}
\mathrm{ =2.3026 \times 10 \times 8.3 \times 600 \log _{10}\left(\frac{10}{100}\right)}
\mathrm{ =-11.4 \times 10^{4} \mathrm{~J}}

Posted by

Ritika Jonwal

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

Karnataka: NEET candidate dies by suicide; no note recovered
anam-khan

CBSE Re-evaluation Row: Dharmendra Pradhan seeks detailed report on technical failures
anam-khan

Before NEET, CMC Vellore’s unique MBBS admissions tested aptitude along with merit; paper-leak restarts debate

Latest Question