Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Medical
  •   The amount of BaSO4 formed upon mixing100 mL of 20.8% BaCl2 solution with    50 mL of 9.8% H2SO4 solution will be :  (B

  The amount of BaSO4 formed upon mixing100 mL of 20.8% BaCl2 solution with   
50 mL of 9.8% H2SO4 solution will be :  (Ba=137, Cl=35.5, S=32, H=1 and O=16)                

 

Option: 1

  23.3    g  
 


Option: 2

 11.65 g   
 


Option: 3

30.6 g  
 


Option: 4

33.2    g 


Answers (1)

best_answer

Moles of \mathrm{BaCl_{2}=\frac{20.8g}{208}=\textup{0.1ml moles}\:of\:H_{2}SO_{4}=\frac{9.8}{98}\times \frac{1}{2}=0.05ml}

\\ \mathrm{BaCl_{2}=\frac{20.8g}{208}=0.1ml }\\ \mathrm{moles\:of\:H_{2}SO_{4}=\frac{9.8}{98}\times \frac{1}{2}=0.05ml}

\\\mathrm{ BaCl_{2}+H_{2}SO_{4}\rightarrow BaSO_{4}+2H^{+}+2Cl^{-} }\\ \\\mathrm{ BaSO_{4}\:formed =0.05ml\\ =0.05\times 11.65g}

Posted by

Deependra Verma

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

From e-rickshaw blunder to police escorts: NEET-UG 2025 undergoes major security overhaul
anam-khan

In NEET UG 2025 plan, question papers under police escort, surveillance of coaching centres
anam-khan

NEET UG 2025 Admit Card LIVE: NTA hall ticket by May 1; download at neet.nta.nic.in; centre list, exam date

Latest Question