Get Answers to all your Questions

header-bg qa

The amphoteric hydroxide is

Option: 1

\mathrm{Be(OH)_2}


Option: 2

\mathrm{Ca(OH)_2}


Option: 3

\mathrm{Sr(OH)_2}


Option: 4

\mathrm{Mg(OH)_2}


Answers (1)

best_answer

For group 2 metal hydroxides,basicity increase down the group as-

\mathrm{\left.\mathrm{Be}(\mathrm{OH})_2<\mathrm{Mg(OH}\right)_2<\mathrm{Ca}(\mathrm{OH})_2<\mathrm{sr(OH)_2}< \mathrm{Ba}(OH)_2}
This is because as the size of metal atom increases \mathrm{M}-\mathrm{OH} band length increases thus readily break e to release \mathrm{OH}^{-} ions which are responsible for the basicity of these solution.
But \mathrm{\mathrm{Be}(\mathrm{OH})_2} show amphoteric character as it reacts with acid and alkali both which is shown in following:-

\mathrm{Be}(\mathrm{OH})_2+2 \mathrm{HCl} \longrightarrow \mathrm{BeCl}_2+2 \mathrm{H}_2 \mathrm{O}(\mathrm{Base})

\mathrm{Be}(\mathrm{OH})_2+2 \mathrm{NaOH} \longrightarrow \mathrm{Na}_2\left[\mathrm{Be(OH)}_4\right] \text { (Acid) }

Hence option 1 is correct.



 

Posted by

avinash.dongre

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks