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  • The block shown in the figure is in equilibrium. Acceleration of the block, just after cutting the string, will be <img alt="" src="https://cdn.entrance360.com/media/uploads/2020/12/09/7-

The block shown in the figure is in equilibrium. Acceleration of the block, just after cutting the string, will be

Option: 1

\frac{3g}{5}


Option: 2

\frac{4g}{3}


Option: 3

\frac{2g}{5}

 


Option: 4

\frac{3g}{4}


Answers (1)

best_answer

Answer (2)

Initially

F_{s}\cos 53^{o}=mg

F_{s}=\frac{5mg}{3}

After cutting the string spring ,force remains same. Hence

F_{net}=\sqrt{\left ( mg \right )^{2}=\left ( \frac{5mg}{3} \right )^{2}+2.mg.\frac{5 mg}{3}\cos\left ( 127^{o} \right )}

F_{net}=\frac{4mg}{3}

a_{net}=\frac{F_{net}}{m}=\frac{4g}{3}

Posted by

shivangi.bhatnagar

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