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The composition (by moles) of effused mixture which initially had equal moles of \mathrm{H}_2, \mathrm{F}_2 and \mathrm{H}_e after 6 effusion steps is  x: 1: y, respectively. Find the value of \mathrm{\left(\frac{x}{y}\right)}

Option: 1

4: 1


Option: 2

8: 3


Option: 3

16: 2


Option: 4

2: 16


Answers (1)

best_answer

Solution: For \mathrm{H}_2 and \mathrm{H}_e

\mathrm{f^{6^{\text {th }}}=\frac{x / y}{1}=\left(\sqrt{\frac{M_{\mathrm{He}}}{M_{\mathrm{H}_2}}}\right)^6}

\mathrm{\begin{array}{r} \frac{x}{y}=(\sqrt{2})^6=(2)^3 \\ \frac{x}{y}=\frac{8}{1}=\frac{16}{2} \end{array}}

Posted by

Irshad Anwar

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