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  • The correct option for the value of vapour pressure of a solution at with benzene to octane in molar ratio 3:2 is : [At <img a

The correct option for the value of vapour pressure of a solution at 45^{o}C with benzene to octane in molar ratio 3:2 is :

[At 45^{o}C vapour pressure of benzene is 280 mm Hg and that of octane is 420 mm Hg. Assume Ideal gas]
 

Option: 1

160 mm of Hg


Option: 2

168 mm of Hg


Option: 3

336 mm of Hg

 


Option: 4

350 mm of Hg


Answers (1)

best_answer

We know this formula for vapour pressure of a solution -

\mathrm{P_\textup{Total}=\chi _A P_A+\chi_B P_B}

At 45oC,

 vapour pressure of benzene  (PA)=   280 mm Hg

 vapour pressure of octane (PB) =  420 mm Hg

 Given, benzene to octane in molar ratio 3:2 

So,

\mathrm{P = \frac{3}{3+2}\times280+\frac{2}{3+2}\times420}

\mathrm{P =168+168}

\mathrm{P =336}

Therefore, the correct option is (3).

Posted by

Kuldeep Maurya

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