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The correct sequence of thermal stability of the following carbonate is.

Option: 1

\mathrm{BaCO}_3<\mathrm{CaCO}_3<\mathrm{SrCO}_3<\mathrm{MgCO}_3


Option: 2

\mathrm{MgCO}_3<\mathrm{CaCO}_3<\mathrm{SrOCO}_3<\mathrm{BaCO} \mathrm{CO}_3


Option: 3

\mathrm{MgCO}_3<\mathrm{SrCO}_3<\mathrm{BaCO}_3<\mathrm{CaCO}_3


Option: 4

None of these


Answers (1)

best_answer

The correct sequence -

\mathrm{HgCO}_3<\mathrm{CaCO}_3<\mathrm{SrCO}_3<\mathrm{BaCO}_3
On moving down the group, ire from \mathrm{\mathrm{Mg}\: to \: \mathrm{Ba}}, atomic radius generally increases. It is due to the addition of shell. As a result, the atomic size increases. \mathrm{\mathrm{CO}_3 2 ^{-}}is a large anion. Hence, more stabilised by \mathrm{\mathrm{Ba}^{2+}} and less stabilised by \mathrm{\mathrm{Mg}^{2+}.}

Hence option 2 is correct.

Posted by

shivangi.bhatnagar

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