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The diffusion coefficient of on ideal gas is Proportional to its mean free path and mean speed The Absolute temperature of an ideal gas is increased 8 atm and its pressure 4 times. As a Result, the diffusion coefficient ot this gas Increase A times. The value at A is?

Option: 1

4


Option: 2

8


Option: 3

6


Option: 4

12


Answers (1)

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\mathrm{\text { Rate of diffusion } \alpha \lambda \alpha \text { U AVg }}

\mathrm{\begin{aligned} & \alpha \frac{1}{\sqrt{2} \pi \sigma^2 N} \times U_{A V g} \\ & \alpha \frac{1}{\sqrt{2} \pi \sigma^2 N} \\ & \propto \frac{U A V g(K T)}{\sqrt{2} \pi \sigma^2 P} \end{aligned}}

\mathrm{\text { Rate of diffuaion } \propto \frac{T^{3 / 2}}{p}}

\mathrm{\frac{\text { r final }}{\text { r inital }}=\frac{(8)^{3 / 2}}{(4)}=4}

Posted by

Ajit Kumar Dubey

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