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  • The dipole moment of each molecule of a paramagnetic gas is <img alt="1.5 \times 10^{-23} \mathrm{Amp} \times \mathrm{m}^2" src="https://entrancecorner.oncodecogs.com/gif.latex?1.5%20%5Ctimes%2010%

The dipole moment of each molecule of a paramagnetic gas is 1.5 \times 10^{-23} \mathrm{Amp} \times \mathrm{m}^2. The temperature of gas is 27^{\circ} \mathrm{C} and the number of molecules per unit volume in it is 2 \times 10^{26} \mathrm{~m}^{-3}. The maximum possible intensity of magnetization in the gas will be.

Option: 1

3 \times 10^3 \mathrm{Amp} / \mathrm{m}


Option: 2

4 \times 10^{-3} \mathrm{Amp} / \mathrm{m}


Option: 3

5 \times 10^5 \mathrm{Amp} / \mathrm{m}


Option: 4

6 \times 10^{-4} \mathrm{Amp} / \mathrm{m}


Answers (1)

best_answer

1.5 \times 10^{-23} \times 10^{26} \times 2

Posted by

vishal kumar

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