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The displacement of the interfering sound waves are y_{1}=9 \sin \omega t and y_2=3 \sin \left(\omega t+\frac{\pi}{2}\right). What is the amplitude of the resultant wave?

Option: 1

9.49


Option: 2

9.14


Option: 3

9.94


Option: 4

8.49


Answers (1)

best_answer


\begin{aligned} & y_1=9 \sin \omega t \\ & y_2=3 \sin \left(\omega t+\frac{\pi}{2}\right) \end{aligned}
amplitude of the resultant wave =\sqrt{90}=9.49

 

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