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The energy of an electron in the first Bohr orbit of H atom is -13.6eV. The possible energy value of the excited state for an electron in Bohr orbits to hydrogen is 

Option: 1

-3.4eV


Option: 2

-4.2eV


Option: 3

-6.8eV


Option: 4

+6.8eV


Answers (1)

best_answer

Energy of any electron is given by 

E = -13.6\ \frac{Z^2}{n^2}\ eV

For the first excited state, putting n=2 , gives the Energy as 

E = -13.6\times \frac{1}{2^2}\ eV\ =-3.4\ eV 

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Nehul

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