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The equation of a wave on a string of linear mass density 0.04 kg/m is given by \gamma =0.02 sin W \left[2\pi\left ( \frac{t}{0.04(s)}-\frac{x}{0.50(m)} \right )\right]

Then tension in the string is 

Option: 1

4.0 N


Option: 2

12.5 N


Option: 3

0.5 N


Option: 4

6. 25 N


Answers (1)

best_answer

Tension, T = \mu v^{2}

                  = \mu \frac{w^{2} }{k^{2}}

                 =0.04\frac{(2\pi/0.004)^{2}}{(2\pi/0.50)^{2}}

                 =6.35N

Posted by

sudhir kumar

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