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  • The equation of a wave on a string of linear mass density 0.04kg/m is given by <img alt="y=0.02 \sin \omega\left[2 \pi\left(\frac{t}{0.04(\mathrm{~s})}-\frac{x}{0.50(\mathrm{~m})}\right)\right

The equation of a wave on a string of linear mass density 0.04kg/m is given by y=0.02 \sin \omega\left[2 \pi\left(\frac{t}{0.04(\mathrm{~s})}-\frac{x}{0.50(\mathrm{~m})}\right)\right]

The tension in the string is 

Option: 1

4.0N


Option: 2

12.5N


Option: 3

0.5N


Option: 4

6.35N


Answers (1)

best_answer

Tension, T=\mu v^2=\mu \frac{\omega^2}{k^2}=0.04 \frac{(2 \pi / 0.004)^2}{(2 \pi / 0.50)^2}

=6.35N

Posted by

Anam Khan

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