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  • The freezing point of nitrobenzene is . When <img alt="1.6 \mathrm{~g}"

The freezing point of nitrobenzene is 4^{\circ} \mathrm{C}. When 1.6 \mathrm{~g} chloroform ( \mathrm{mol.wt} =120 ) is dissolved in 110 g of nitrobenzene, freezing point will be \mathrm{3.2^{\circ} \mathrm{C}}. when 0.8 g of acetic acid dissolved in 110 g in nitrobenzene, freezing point of solution is 2.46^{\circ} \mathrm{C}. If formula of acetic acid is \left(\mathrm{CH}_2 \mathrm{O}\right)_\text{n}. What is value of n

Option: 1

n = 1.3


Option: 2

n = 5.5


Option: 3

n = 9.8


Option: 4

n = 4.5


Answers (1)

best_answer

\mathrm{\Delta T_{f}=k_f\times m}

\begin{aligned} 4-3.2 & =\mathrm{k_f \times \frac{1.6}{120} \times \frac{1000}{110}} \\ \mathrm{So, k_f} & =8.8 \\ 4-2.64 & =\mathrm{8.8 \times \frac{0.8}{M} \times \frac{1000}{110}} \end{aligned}

So, \mathrm{M=40}

For, \mathrm{(CH_{2}O)_{n}}            

\mathrm{30\times n=40}

\mathrm{n=\frac{40}{30}}

\mathrm{n=1.3}

Posted by

Suraj Bhandari

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