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The length of the cylinder is measured with a measuring rod with a minimum count of  0.1\ cm. Its diameter is measured with a vernier caliper minimum count of 0.01\ cm . Assume a length of 5\ cm and a radius of 2\ cm. The volume calculation error percentage is:

Option: 1

1%


Option: 2

2%


Option: 3

3%


Option: 4

4%


Answers (1)

best_answer

Volume of the cylinder,  V={\pi r}^2l

Percentage error in volume

\frac{\Delta V}{v}\times 100=\frac{2\Delta r}{r}\times 100+ \frac{\Delta l}{l}\, \times 100

Or, 2\times\frac{0.01}{2.0}\times100\ +\frac{0.1}{5.0}\times100

Or, \left(1%+2%\right)=3%

Posted by

Nehul

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