Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa

The loudspeakers L_{1} and L_{2} driven. As the frequency of the oscillators increases from zero, the detector at D is recorded as a series of maximum and minimum signals. What is the frequency at which the first maximum is observed? (speed of sound =330 \mathrm{~m} / \mathrm{s} )

 

Option: 1

165 \mathrm{~Hz}


Option: 2

330 \mathrm{~Hz}


Option: 3

495 \mathrm{~Hz}


Option: 4

660 \mathrm{~Hz}


Answers (1)

best_answer

L_{2} D=\sqrt{(40)^{2}+(9)^{2}}=41 \mathrm{~m}

path difference,

\begin{gathered} \Delta x=L_{2} D-L_{1} D=1 \mathrm{~m}=\lambda \\ \therefore f=\frac{v}{\lambda}=330 \mathrm{~Hz} \end{gathered}

Posted by

admin

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

Uttarakhand NEET Counselling 2026: CM Dhami expands probe to include other reserved categories
anam-khan

NEET: Nilekani panel’s first report by month-end; SC plans NTA office visit
anam-khan

Uttarakhand NEET Counelling: Quota certificates under lens after 5 booked for securing MBBS seat via fake ones

Latest Question