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  • The loudspeakers  driven. As the frequency of the oscillator increases

The loudspeakers \small L_1\ and\ L_2 driven. As the frequency of the oscillator increases from zero, the detector at \small D recorded at a series of maximum and minimum signal. What is the frequency at which the first maximum is observed? (speed of sound = \small 330 \mathrm{~m} / \mathrm{s})

Option: 1

165 Hz


Option: 2

330 Hz


Option: 3

495 Hz


Option: 4

660 Hz


Answers (1)

best_answer

L_2 D=\sqrt{(40)^2+(9)^2}=41 \mathrm{~m}

Path\ difference, \\ \Delta x=L_2 D-L_1 D=1 m=\lambda

f=\frac{v}{\lambda}=330 \mathrm{~Hz}

Posted by

chirag

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