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  • The mass of a hydrogen molecule is  . If

The mass of a hydrogen molecule is  3.32 \times 10^{27} \mathrm{Kg}. If 10^{24} a hydrogen molecule strikes per second, a fixed wall of the area 3 \mathrm{~cm}^{2}$ at $60^{\circ} to the normals and rebound elastically with a speed of 10^{4} \mathrm{~ms}^{-1} the pressure on the wall is

Option: 1

2.35 \times 10^{3} \mathrm{Nm}^{-2}


Option: 2

4.70 \times 10^{3} \mathrm{Nm}^{-2}


Option: 3

1.10 \times 10^{{5}} \mathrm{Nm}^{-2}


Option: 4

4.70 \times 10^{2} \mathrm{Nm}^{-2}


Answers (1)

best_answer

As p_{1}=p_{t}

The net force on the wall,

F=d p / d t=2 n p_{1} \cos 60^{\circ}=2 n m v \cos 60^{\circ}

Here, n is the number of molecules of hydrogen strikes per second.

\begin{aligned} & \text { Pressure }=F / A=\left(2 n m v \cos 60^{\circ}\right) / \text { Area } \\ & =\frac{2 \times 10^{29} \times 3.32 \times 10^{-27} \times 10^{4} \times 1 / 2}{3 \times 10^{-4}} \\ & =1.10 \times 10^{2} \mathrm{Nm}^{-2} \end{aligned}

Posted by

Ritika Harsh

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