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The mean free path for a gas, with molecular diameter d and number density n canbe expressed as:
Option: 1
$\frac{1}{\sqrt2 n\pi d}$

Option: 2
$\frac{1}{\sqrt2 n\pi d^2}$

Option: 3
$\frac{1}{\sqrt2 n^2\pi d^2}$

Option: 4
$\frac{1}{\sqrt2 n^2\pi^2 d^2}$

Answers (1)

best_answer

Mean free path is given by,

$\lambda=\frac{1}{\sqrt{2} \pi n d^{2}}$

Posted by

Gunjita

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