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The minimum pressure required to compress 600\; dm^{3} of a gas at 1 bar to 150\; dm^{3} at 40^{o}C is

Option: 1

0.2 bar
 


Option: 2

1.0 bar


Option: 3

2.5 bar

 


Option: 4

4.0 bar


Answers (1)

best_answer

From Boyle's law,

P_{1}V_{1}=P_{2}V_{2}

\Rightarrow 1 \times 600=P_{2}\times 150

\Rightarrow P_{2}=4 \; bar

Hence, the correct answer is option 4.

Posted by

Irshad Anwar

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