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  • The normal density of a metal is  and its bulk modulus is B. The increase in the dens

The normal density of a metal is \mathrm{\rho } and its bulk modulus is B. The increase in the density of a block of the metal when an excess pressure P is applied to it normally on all sides is

Option: 1

\mathrm{\frac{\rho P}{B}}


Option: 2

\mathrm{\frac{\rho B}{P}}


Option: 3

\mathrm{\frac{P}{\rho B}}


Option: 4

\mathrm{\rho P B}


Answers (1)

best_answer

The decrease in the density of the block is

                                 \mathrm{ \Delta V=\frac{V P}{B} }

If M is the mass of the block, its density is \mathrm{\rho=\frac{M}{V}}.

Due to decrease \mathrm{\Delta V} in its volume, the increase in its density is

\mathrm{ \Delta \rho=\frac{M}{\Delta V}=\frac{M B}{V P}=\frac{\rho B}{P} }

So the correct choice is (b).

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chirag

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