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  • The number of revolutions made by the electron in one second in the 2nd Bohr orbit of the hydrogen atom is?Option: 1 <img alt="6.28\times{1

The number of revolutions made by the electron in one second in the 2nd Bohr orbit of the hydrogen atom is?

Option: 1

6.28\times{10}^{12}


Option: 2

6.28\times{10}^{13}


Option: 3

8.23\times{10}^{14}


Option: 4

8.23\times{10}^{13}


Answers (1)

best_answer

Let V be the speed of electron 

Number of revolution =\ rps\ =\frac{v}{2\pi r}

v\ =\frac{nh}{2\pi mr}

So rps\ =\frac{nh}{4\pi^2mr^2}

=\frac{nh}{4\pi^2}\left(\frac{a_0n^2}{Z}\right)

=\frac{Z^2h}{4\pi^2}ma_02n^3

=\ 6.626\times{10}^{-32}\times\frac{\left(1\right)^2}{4}\times\left(3.14\right)^2\times9.1\times{10}^{-31}\times(0.53\ \times{10}^{-10})\times\left(2\right)^3=8.23\times{10}^{14}

Posted by

shivangi.bhatnagar

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