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  • The oxidation potential (in V) of the hydrogen electrode at pH = 10 and <img alt="P _{H_{2}}=10\: a t m" src="https://entrancecorner.oncodecogs.com/gif.latex?P%20_%7BH_%7B2%7D%7D%3D10%5C%3A%20

The oxidation potential (in V) of the hydrogen electrode at pH = 10 and P _{H_{2}}=10\: a t m

Option: 1

0.71


Option: 2

0.53


Option: 3

0.59


Option: 4

0.62


Answers (1)

best_answer

\mathrm{H_2\rightarrow 2H^++2e^-}

\\E = E ^0 - \frac{0.059}{n}log \frac{[H^+]}{P_{H_2}}\\\\\\ E = 0-\frac{0.0591}{1}log \frac{10^{-10}}{\sqrt{10}}

\mathrm{E=0.0591 \times 10.5 = 0.62\ V}

 

Posted by

SANGALDEEP SINGH

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