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  • The oxidation state of the most electronegative element is the products of  the reaction, <img alt="\mathrm{BaO}_2" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7BBaO%7D_2" /

The oxidation state of the most electronegative element is the products of  the reaction, \mathrm{BaO}_2 with dill. \mathrm{H}_2 \mathrm{SO}_4 are -
 

Option: 1

0,1


 


Option: 2

-1,-2
 


Option: 3

-2,-1


Option: 4

0,-2


Answers (1)

best_answer

The reaction involved is -

\mathrm{BaO}_2+\mathrm{H}_2 \mathrm{SO}_4 \longrightarrow \mathrm{BaSO}_4+\mathrm{H}_2 \mathrm{O}_2

The most electronegative atom, oxygen in \mathrm{\mathrm{BaSO}_4 \: and\: \mathrm{H}_2 \mathrm{O}_2} has -2 and -1 Oxidation state respectively.

Hence option 3 is correct.

Posted by

HARSH KANKARIA

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