Browse by Stream
QnA
Home

Get Answers to all your Questions

header-bg qa
  • Home
  • Medical
  • The phase difference between displacement and acceleration of a particle in a simple harmonic motion is: Option: 1

The phase difference between displacement and acceleration of a particle in a simple harmonic motion is:
Option: 1 \mathrm{\pi \ rad}
Option: 2 \mathrm{\frac{3\pi}{2} \ rad}
Option: 3 \mathrm{\frac{\pi}{2} \ rad}
Option: 4 zero

Answers (1)

best_answer

$$\begin{aligned} &\text { SHM is represented by }\ displacement= \mathrm{x}=\mathrm{A} \sin \omega \mathrm{t}\\ &\text { Then, the velocity and acceleration after differentiation will be }\\ &\mathbf{v}=\mathbf{A} \omega \cos \omega \mathbf{t}\\ &\mathrm{a}=-\mathrm{A} \omega^{2} \sin \omega \mathrm{t}=\mathrm{A} \omega^{2} \sin (\omega \mathrm{t}+\pi) \end{aligned}

So the phase difference between x & a= \mathrm{\pi \ rad}

Posted by

Deependra Verma

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

NEET-UG Fraud: AIIMS Jodhpur MBBS student arrested 5 years after using dummy candidate in exam
anam-khan

NTA NEET UG 2025 Live: How to raise objection at neet.nta.nic.in; last date, result, direct link updates
anam-khan

NEET UG 2025 question sparks confusion, but NTA already has a rule

Latest Question