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  • The pi bond in is formed by overlapping of Option: 1</

The pi bond in \mathrm{SO}_2 is formed by overlapping of 

Option: 1

\sigma


Option: 2

\mathrm{p \pi-p \pi \text { and } \sigma}


Option: 3

\mathrm{p \pi-d \pi \, \, \& \, \, p \pi-p \pi}


Option: 4

\mathrm{\text { only } p \pi-d \pi}


Answers (1)

best_answer

The sulphur dioxide molecule contains 2 \sigma, 2 \pi bonds and one lone pair of electrons. S atom contains 6 valence electrons out of which it shares 2 electrons with 2 \mathrm{O} atoms to form 2 sigma bonds.It also shares 2 electrons with 2 \mathrm{O} atoms to form \pi bonds. The remaining 2 electrons appear as one lone pair of electrons. \mathrm{SO}_2 molecule has bent geometry. The \mathrm{S} atom undergoes \mathrm{sp}^2 hybridization.

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Ritika Jonwal

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