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  • The Pressure of a Moist was at is <img alt="8 \mathrm{~atm}" src="htt

The Pressure of a Moist was at 27^{\circ} \mathrm{C} is 8 \mathrm{~atm}. The volume of the container is doubled at the same temperature. \left[P_{H_2}\right. at \left.27^{\circ} \mathrm{C}=\cdot 2 \mathrm{~atm}\right] The New pressure of the Moist gas is ..... \times 10^{-1} \mathrm{~atm}

Option: 1

2.2 atm


Option: 2

4.1 atm


Option: 3

3.2 atm


Option: 4

5.1 atm


Answers (1)

best_answer

Dalton's law,

\left.\bar{P}=P_a+P_v\right]

\begin{aligned} & P_{\text {gas }}+P_{\mathrm{H}_2} \mathrm{O}=8 \mathrm{atm} \\ & P_{g a s}=8 \--. 2 atm \\ & =7.8 \text { atm } \\ & \end{aligned}

As volume is doubled

\left(P_{\text {gas }}\right)_{\text {New }}=3.9 \text { atm }
Now Total Pressure

=3.9+2=4.1 \mathrm{~atm}

Posted by

shivangi.shekhar

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