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  • The pressure ot o Moist gas at  is 2 atm. The volume of container

The pressure ot o Moist gas at 20^{\circ} \mathrm{C} is 2 atm. The volume of container is doubled at the same Temperature. The New Pressure of Moist Gas ...\times 10^{-1} \mathrm{~atm} [Given vapour fissure of water at 20^{\circ} \mathrm{C}=4 \mathrm{~atm} ]

Option: 1

1.2


Option: 2

2.2


Option: 3

3.2


Option: 4

2.4


Answers (1)

 According to Dalton's Law 

\mathrm{P=P_a+P_V .}

\mathrm{\begin{aligned} & P_{\text {gas }}+P_{\mathrm{H}_2 \mathrm{O}}=2 \\ & P_{\text {gas }}=2-\cdot 4=1.6 \mathrm{~atm} \end{aligned}}

As volume is doubled

\mathrm{\text { Pgas New }=.8 \mathrm{atm}}

\mathrm{\text { New Total Pressure }=.8+.4=1.2}

Posted by

Sumit Saini

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