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  • The right option for the mass of  produced by 20 g of 20% pure limestone is (Atomic mass of Ca =40)

The right option for the mass of CO_2 produced by 20 g of 20% pure limestone is (Atomic mass of Ca =40)

CaCO_3\overset{1200K}{\rightarrow} CaO+CO_2
 

Option: 1

1.12g


Option: 2

1.76g


Option: 3

2.64g


Option: 4

1,32g


Answers (1)

best_answer

\begin{aligned} & \text { \% purity of a reactant } \frac{(\text { amount of pure reactant })}{\text { total amount of sample }} \times 100 \\ & 20=\frac{\text { amount of pure reactant } \times 100}{20 \mathrm{~g}} \\ & \therefore \text { pure substance }=4 \mathrm{~g} \mathrm{CaCO}_3 \\ & \mathrm{CaCO}_3 \longrightarrow \mathrm{CaCO}+\mathrm{CO}_2 \\ & 100 \mathrm{~g} \\ & \therefore 100 \text { of } \mathrm{CaCO}_3 \longrightarrow 44 \mathrm{~g} \text { of } \mathrm{CO}_2 \text { is produced } \\ & \therefore 4 \mathrm{~g} \text { of } \mathrm{CaCO}_3 \longrightarrow \frac{44}{100} \times 4 \mathrm{~g}\ \mathrm{of}\ {\mathrm{CO}_2 \text { will be produced }} \\ & =1.76 \mathrm{~g} \end{aligned}

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vinayak

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