Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Medical
  • The Root mean square speed of Molecule in sample at Temperature <img alt="\mathrm{T}" src

The Root mean square speed of \mathrm{O}_{2} Molecule in sample at Temperature \mathrm{T} is \mathrm{'A'}.

If the Temperature is doubled, then oxygen molecules dissociate into atom.
The Root Mean square speed of oxygen atom become \mathrm{n} time of \mathrm{'A'} find value of \mathrm{n} ?

Option: 1

\sqrt{\frac{32}{16}}


Option: 2

\sqrt{\frac{16}{32}}


Option: 3

\sqrt{\frac{32}{18}}


Option: 4

\sqrt{\frac{3-2}{16}}


Answers (1)

best_answer

\mathrm{V \text {rMS }=\sqrt{\frac{3 R T}{m}} }
\mathrm{A=\sqrt{\frac{3 R T}{32}}-(i) }
\mathrm{\text { vrMs }=\sqrt{\frac{3 R \times 2 T}{16}}-(ii)}

Dividing equation (i) & (ii)
\mathrm{\frac{A}{\text {VrMs }} =\sqrt{\frac{16}{32}} }
\mathrm{\text { So, vrms } =\sqrt{\frac{32}{16}} A }

\mathrm{\text { so } =n=\sqrt{\frac{32}{16}} }

Posted by

Divya Prakash Singh

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

NEET UG Counselling 2026 LIVE: MCC round 3 seat allotment today, list of NRI candidates out
anam-khan

NEET Paper Leak: Nandan Nilekani-led panel consults ex-ISRO chief K Radhakrishnan on NTA exam reforms
anam-khan

NEET Paper Leak: CISF to guard NTA premises; stricter monitoring for 'confidential' areas

Latest Question