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The specific conductance of a decinormal solution of KCl is 0.056 Scm^{-1}. The resistance of the cell was 112 ohm. What is the cell constant (in cm-1)? 

Option: 1

0.0005


Option: 2

0.06272


Option: 3

0.6272


Option: 4

6.272


Answers (1)

best_answer

The conductance of electrolytic solutions(G) is the inverse of resistance R.

We know, 
\kappa = G \times G^*

\\\therefore G^*=\frac{\kappa }{G}=\kappa \times R \\\\ \Rightarrow G^* = 0.056 \times 112=6.272 cm^{-1}
 

Posted by

himanshu.meshram

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