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The state of hybridization of C_{2} , C_{3}, C_{5}, and C_{6} of the hydrocarbon,

CH_{3}- \underset{CH_{3}}{ \underset{|} { \overset {CH_{3}}{\overset {|}{_{6}C}}}}- \underset{5}{CH}= \underset{4}CH- \overset{CH_{3}}{\overset {|}{\underset{3}{CH}}} -\underset{2}C\equiv \underset{1}CH

 

is in the following sequence:

Option: 1

sp^{3}, sp^{2}, sp^{2}  and sp


Option: 2

sp, sp^{2}, sp^{2}  and sp^{3}


Option: 3

sp, sp^{2}, sp^{3} and \:sp^{2}


Option: 4

sp, sp^{3}, sp^{2}  and sp^{3}


Answers (1)

best_answer

Hybridisation of C2\rightarrow sp(\sigma \:bond=2)\\

C_{3}\rightarrow sp^{3}(\sigma \:bond=4)\\ C_{5}\rightarrow sp^{2}(\sigma \:bond=3)\\ C_{6}\rightarrow sp^{3}(\sigma \:bond=4)

Posted by

HARSH KANKARIA

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