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The temperature of a room heated by a heater is 20^{o}C when outside temperature is -20^{o}C and it is 10^{o}C when the outside temperature is -40^{o}C. The temperature of the heater is

Option: 1

40^{o}C


Option: 2

60^{o}C


Option: 3

100^{o}C

 


Option: 4

75^{o}C


Answers (1)

best_answer

Answer (2)

Under steady condition

Heat released to the room = heat dissipated out of the room

Hence \theta -20=\alpha \left [ 20-\left ( -20 \right ) \right ]

and     \theta -10=\alpha \left [ 10-\left ( -40 \right ) \right ]

on solving we get \theta =60^{o}C

Posted by

Divya Prakash Singh

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