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  • The temperature of gas is . To what Temperature shou

The temperature of gas is \small 27^{\circ} \mathrm{C}. To what Temperature should it be heated to double its Kinetic Energy.

Option: 1

327^{\circ} \mathrm{C}


Option: 2

427^{\circ} \mathrm{C}


Option: 3

600^{\circ} \mathrm{C}


Option: 4

500^{\circ} \mathrm{C}


Answers (1)

best_answer

\begin{aligned} & KE_2=\frac{3}{2} K_BT \\ & KE_1=\frac{3}{2} K_BT \end{aligned} 

KE_2=2 KE_1

2 \times \frac{3}{2} K_B T=\frac{3}{2} K_B T \times 2

K_B T=\frac{3}{2} K_B T \times 2

T=2 \times T

T=600-223=327^{\circ} \mathrm{C}

 

Posted by

Suraj Bhandari

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