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The temporary hardness of a water sample is due to compound \mathrm{x}. Boiling this sample converts \mathrm{x} to compound \mathrm{y} . \mathrm{x\: and \: y}respectively are-

 

Option: 1

\mathrm{Mg}\left(\mathrm{HCO}_3\right)_2$ and $\mathrm{Mg}(\mathrm{OH})_2
 


Option: 2

\mathrm{\mathrm{Ca}\left(\mathrm{HCO}_3\right)_2 and\: \mathrm{Ca}(\mathrm{OH})_2}
 


Option: 3

\mathrm{\mathrm{Mg}\left(\mathrm{HCO}_3\right)_2 \: and \: \mathrm{MgCO}_3}


Option: 4

\mathrm{\mathrm{CaCHCO})_2\: and \: \mathrm{CaO}}


Answers (1)

best_answer

The temporary hardness of water sample is due to compound \mathrm{x [ \left.\mathrm{Mg}(\mathrm{HCo_3})_2\right]} Boiling of this sample converts \mathrm{x } to compound \mathrm{y\left[\mathrm{Mg}(\mathrm{OH})_2\right] }. Temporary hardness in due to presence of magnesium and calcium hydrogen carbonates. It can be removed by boiling.

\mathrm{ \mathrm{Mg}\left(\mathrm{HCO}_3\right)_2 \stackrel{\text { heating }}{\longrightarrow} \mathrm{Mg}(\mathrm{OH})_2 \downarrow+2 \mathrm{CO}_2 \uparrow }

\mathrm{ \mathrm{Ca}\left(\mathrm{HCO}_3\right)_2 \text { heating } \rightarrow \mathrm{CaCO} \downarrow+\mathrm{H}_2 \mathrm{O}+\mathrm{CO}_2 \uparrow }

Hence option 1 correct.

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Gunjita

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