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  • The torque due to gravity at any time about point of projection if a body is projected with velocity

The torque due to gravity at any time \mathrm{t} about point of projection if a body is projected with velocity u at an angle \mathrm{\theta.}
 

Option: 1

\mathrm{mgu\sin \theta t }
 


Option: 2

\mathrm{m g u\tan \theta t}
 


Option: 3

\mathrm{mgu\cos \theta t}
 


Option: 4

\mathrm{2 m g u\cos \theta t}


Answers (1)

best_answer

\mathrm{\tau=F r_{\perp}}

Now, \mathrm{ x=u_x t+\frac{1}{2} a_x t^2 }

         \mathrm{ x=u \cos \theta t }

        \mathrm{ \tau=m g u \cos \theta t }

Hence option 3 is correct.

 




 

Posted by

Shailly goel

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