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  • The vapour pressure of an aqueous solution of glucose is of <img alt="\mathrm{Hg}" sr

The vapour pressure of an aqueous solution of glucose is 720 \mathrm{~mm} of \mathrm{Hg} at 373 \mathrm{~K}, the molality is

 

Option: 1

0.714


Option: 2

1.476


Option: 3

3.086


Option: 4

 0.628


Answers (1)

best_answer

\mathrm{\frac{p^{0}-p_{s}}{p_{s}} =\frac{w_{1} \times m_{2}}{m_{1} \times w_{2}}}

\mathrm{\frac{p^{0}-p_{s}}{p_{s}} =\frac{w_{1} \times 1000}{m_{1} \times w_{2}} \times \frac{m_{2}}{1000}=M \times \frac{m_{2}}{1000} }

\mathrm{\frac{760-720}{720} =M \times \frac{18}{1000} \quad }


\mathrm{m=\frac{40 \times 1000}{720 \times 18} }

\mathrm{m=3.086 }

Posted by

Kuldeep Maurya

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