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The vapour pressure of pure liquid \mathrm{A} is is 75 torr at 27^{\circ} \mathrm{C}.  It forms an ideal solution with another liquid B. The mole fraction of \mathrm{B} is 0.4 and total vapour pressure of the solution is 94 torr at 27^{\circ} \mathrm{C}. The vapour pressure of pure liquid Bat 27^{\circ} \mathrm{C} is 

Option: 1

136.7 \mathrm{~mm\: Hg}


Option: 2

122.5 \mathrm{~mm\: Hg}


Option: 3

172.7 \mathrm{~mm\: Hg}


Option: 4

236.5 \mathrm{~mm\: Hg}


Answers (1)

\mathrm{ \rho_{A}=75 \text { torr; } \rho_{T}=94 \text { torr }}

\mathrm{ x_{B}=0.4 ; x_{A}=1-0.4 }

\mathrm{ x_{A}=0.6}

\mathrm{ P ^{\circ}_B= ?}
\mathrm{ P_{T}=P^{0}_A x_{A}+P_{B}^{0} x_{B}}
\mathrm{ 9{4}=75 \times 0.6+P^{0}_B \times 0.4 }
\mathrm{94=45+0.4 P^{\circ} _B }
\mathrm{49=0.4 P^{\circ}_B }
\mathrm{P^{\circ}_B=122.5 \, \mathrm{mm\, Hg} }

Posted by

Ramraj Saini

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