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The vibrations of a string of length 40 cm fixed at both ends are represented by the equation y=4\sin \left ( \frac{\pi x}{10} \right ).\cos \left ( 96\pi t \right ), where x and y are in cm and t is in seconds. Maximum displacement of a point at x=5 cm is

Option: 1

4 cm


Option: 2

2 cm


Option: 3

5 cm

 


Option: 4

Zero


Answers (1)

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Answer (1)

Maximum displacement at x=5

y=4 \sin \left ( \frac{5\pi }{10} \right )=4 \sin\frac{\pi }{2}=4\; cm

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shivangi.shekhar

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