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The work function of silver and sodium are 4.6 and 2.3 respectively. The ratio of the slope of the stopping potential versus frequency plot for silver to that of sodium is: -
 

Option: 1

\frac{e}{h}


Option: 2

\frac{h}{e}


Option: 3

\frac{2 h}{e}


Option: 4

\frac{e}{2 h}


Answers (1)

best_answer

\begin{aligned} \mathrm{e V_0 }& =\mathrm{h f-w} \\ \mathrm{v_0 }& =\mathrm{\left(\frac{h}{e}\right) f-\frac{\omega}{e}} \end{aligned}

Vo versus f graph is a straight line with slope \mathrm{=\frac{h}{e}=a} universal constant.
le the ratio of two slopes should be 1 .

Posted by

Anam Khan

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