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  • Three waves, <img alt="y_2=A \ sin(kx-wt+\phi)" src="https:

Three waves,

y_1=A \ sin(kx-wt)

y_2=A \ sin(kx-wt+\phi)

y_3=A \ sin(kx-wt+2\phi)

are superimposed so that y_1+y_2+y_3=0 at all positions. Then, the value of \phi is:

 

 

Option: 1

\frac{2\pi}{3}


Option: 2

\frac{\pi}{3}


Option: 3

\frac{4\pi}{3}


Option: 4

\frac{\pi}{2}


Answers (1)

best_answer

A_1, A_2, A_3 all are equal to A acting at angles shown in figure. We can see that resultant of these three come out to be zero.

\phi = \frac{2\pi}{3}= 120^{\cdot }

2\phi = 240^{\cdot }

Posted by

sudhir kumar

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