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  • Time taken for an electron to complete one revolution in the Bohr orbit of hydrogen atom isOption: 1 <img alt="\frac{4\pi^2 mr^{2}}{nh}" src="/latex-

Time taken for an electron to complete one revolution in the Bohr orbit of hydrogen atom is

Option: 1

\frac{4\pi^2 mr^{2}}{nh}


Option: 2

\frac{nh}{4\pi^{2} mr}


Option: 3

\frac{nh}{4\pi^{2} mr^{2}}


Option: 4

\frac{h}{4\pi mr}


Answers (1)

best_answer

We know that , time period is the time taken for one complete revolution

\therefore T = \frac{2\pi r}{V} \ \ \ ......(1)

Now, we know that angular momentum of an electron in n^{th} orbit is given by 

mVr= \frac{nh}{2\pi}\Rightarrow V=\frac{nh}{2\pi mr} ...... (2)

From equations (1) and (2), 

\therefore T = \frac{2\pi r}{V} = \frac{2\pi r}{\frac{nh}{2\pi m r}}= \frac{4\pi^2mr^2}{nh}

Posted by

Ajit Kumar Dubey

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