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Two cyllinders of same cross-section and length \mathrm{L} but made of two material of densities \mathrm{d_1} and \mathrm{d_2} are cemented together to form a cylinder of length \mathrm{ 2 \mathrm{~L}}. The combination floats in a liquid of density d with a length \mathrm{ L / 2} above the surface of the liquid. If \mathrm{ d_1>d_2} then :

Option: 1

\mathrm{d_1>\frac{3}{4} d}


Option: 2

\mathrm{\frac{d}{2}>d_1}


Option: 3

\mathrm{\frac{\mathrm{d}}{4}>\mathrm{d}_1}


Option: 4

\mathrm{d<d_1}


Answers (1)

\mathrm{\begin{aligned} & d_1 A L+d_2 A L=\frac{3}{2} \text { LAd } \\ & d_1+d_2=\frac{3 d}{2} \\ & \therefore d_1>\frac{3 d}{4} \end{aligned}}

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Kshitij

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