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  • Two different isotherm  representing the pressure  P and volume  V at a given temperature  of the same ideal gas are shown for masses <img alt="m_1

Two different isotherm  representing the pressure  P and volume  V at a given temperature  of the same ideal gas are shown for masses m_1  and  m_2 then 
 

Option: 1

m_1>m_2


Option: 2

m_1=m_2


Option: 3

m_1<m_2


Option: 4

None of these


Answers (1)

best_answer

P V=\mu R T=\frac{m}{M} R T \text {. }

for first graph,  P= \frac{m_1}{M}\,\,\frac{RT}{V_1}\rightarrow (i)

for second graph, P=\frac{m_2}{M}\, \frac{R T}{V_2}\rightarrow (ii)

from equation (i) and (ii) we get,

\frac{m_1}{m_2}=\frac{V_1}{V_2} \Rightarrow m \propto \frac{1}{V} \\

V_2>V_1 \Rightarrow m_1<m_2

Posted by

Devendra Khairwa

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