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Two drops of same radius are falling through air with steady velocity of V \mathrm{~cm} / \mathrm{s}. If the two drops coalesce, what would be the terminal velocity?

Option: 1

4v


Option: 2

1/3v


Option: 3

2v


Option: 4

64v


Answers (1)

best_answer

\mathrm{\begin{aligned} & 2 \frac{4}{3} \pi r^3=\frac{4}{3} \pi R^3 \\ & R=2^{1 / 3} \cdot r \\ & v \propto r^2 \\ & v \propto 4^{1 / 3} \end{aligned}}

Posted by

manish painkra

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