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  • Two gas bulbs are connected by a thin tube. Calculate the partial pressure of helium after the connective value is opened at a constant temperature of <img alt="27^{\circ} \mathrm{C} \mathrm{}" src

Two gas bulbs are connected by a thin tube. Calculate the partial pressure of helium after the connective value is opened at a constant temperature of 27^{\circ} \mathrm{C} \mathrm{}.
 

Option: 1

1 atm


Option: 2

0.328 atm


Option: 3

1.64 atm


Option: 4

0.16 atm


Answers (1)

best_answer

\mathrm{n_{\text {He }}=\frac{P V}{R T}=\frac{0.63 \times 1.2}{0.0821 \times 300}=0.03 \quad x_{H e}=\frac{n_{\text {He }}}{n_{\text {He }}+n_{\text {He }}}=\frac{0.03}{0.03+0.39}}
                                                                                                                       \mathrm{= 0.0714}

\mathrm{n_{\text {Ne }}=\frac{2.8 \times 3.4}{0.0821 \times 300}=0.39}

\mathrm{\text { Total pressure } =P_{1} V_{1}+P_{2} V_{2}=P_{R}\left(V_{1}+V_{2}\right)}

\mathrm{\Rightarrow(0.63 \times 1.2)+(2.8 \times 3.4)=P_{R}(1.2+3.4)}
\mathrm{\Rightarrow P_{R}=2.23 \mathrm{~atm} \quad \therefore P_{\text {He }}=x_{H e} \times P_{R}}
\mathrm{=0.0714 \times 2.23=0.16 \text { atm }}  (option d)

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