Get Answers to all your Questions

header-bg qa

Two glass bulbs A and B are connected by a very Small Tube having a stop-cock.
Bulb A has a volume \mathrm{50\, cm^{3}} and contained the gas, mutule bulb B was empty.
On opening the stop-cocts. the pressure fall down to \mathrm{50%}
The volume at bulb B must be

Option: 1

\mathrm{50\, cm^{3}}


Option: 2

\mathrm{150\, cm^{3}}


Option: 3

\mathrm{100\, cm^{3}}


Option: 4

\mathrm{250\, cm^{3}}


Answers (1)

best_answer

\mathrm{P_{1}=1 \text { atm } P_{2}=1 \text { atm } \times \frac{50}{100}=50 \mathrm{~atm}}
\mathrm{v_{1}=50 \mathrm{~cm}^{3} \: \: v_{2}=?}

At constant temperature

\mathrm{\Rightarrow P_{1} v_{1}=P_{2} v_{2}}
\mathrm{ \Rightarrow \text { so } v_{2}=\frac{P_{1} v_{1}}{P_{2}}}
\mathrm{ =\frac{1 \times 50}{0.50}=100 \mathrm{~cm}^{3}}

Hence the volume of bulb
\mathrm{ B=(100-50) \mathrm{cm}^{3}=50 \mathrm{~cm}^{3}}

Posted by

Riya

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks